com.ibm.ras
Class RASMaskChangeEventjava.lang.Object | +--java.util.EventObject | +--com.ibm.ras.RASMaskChangeEvent
- All Implemented Interfaces:
- java.io.Serializable
- public class RASMaskChangeEvent
- extends java.util.EventObject
RASMaskChangeEvent indicates that a change has occurred in a message or trace mask. It is sent from a RASIMaskChangeGenerator to a RASIMaskChangeListener.
- See Also:
- Serialized Form
Field Summary
Fields inherited from class java.util.EventObject source
Constructor Summary RASMaskChangeEvent(java.lang.Object source, long oldMask, long newMask, boolean flag)
Creates a RASMaskChangeEvent.
Method Summary long getNewMask()
Gets the new message or trace mask value.long getOldMask()
Gets the old message or trace mask value.boolean isMessageMask()
Determines if the changed mask was a message mask or a trace mask.
Methods inherited from class java.util.EventObject getSource, toString
Methods inherited from class java.lang.Object clone, equals, finalize, getClass, hashCode, notify, notifyAll, wait, wait, wait
Constructor Detail RASMaskChangeEvent
public RASMaskChangeEvent(java.lang.Object source, long oldMask, long newMask, boolean flag)
- Creates a RASMaskChangeEvent.
- Parameters:
- source - The object which generated this RASMaskChangeEvent
- oldMask - The old mask value.
- newMask - The new mask value.
- flag - true if this mask is a message mask and false if it is a trace mask.
Method Detail getOldMask
public long getOldMask()
- Gets the old message or trace mask value.
- Returns:
- The old mask value.
getNewMask
public long getNewMask()
- Gets the new message or trace mask value.
- Returns:
- The new mask value.
isMessageMask
public boolean isMessageMask()
- Determines if the changed mask was a message mask or a trace mask.
- Returns:
- true if this changed mask is a message mask and false if it is a trace mask.
WebSphere is a trademark of the IBM Corporation in the United States, other countries, or both.
IBM is a trademark of the IBM Corporation in the United States, other countries, or both.