Obtaining a controller for working with resources

To modify, create, or delete portal resources by using the Controller SPI, you first need to create a controller.

You do this by using a JNDI based lookup for the correct "home" interface, that is, the corresponding read-only interface. The provider lookup for a controller home is possible from servlet level code and portlets.

The following controllers are available via JNDI:
ContentModelController

To obtain a ContentModelController, perform a lookup for the string ContentModelControllerHome.CONTENT_MODEL_CONTROLLER_JNDI_NAME.

PortletModelController

To obtain a ContentModelController, perform a lookup for the string PortletModelControllerHome.PORTLET_MODEL_CONTROLLER_JNDI_NAME.

The LayoutModelController cannot be obtained via a JNDI lookup. You obtain it through its associated ContentModelController.
Example - Obtaining a content model controller:

ContentModelController result = null;
final Context ctx = new InitialContext();
final ContentModelControllerHome home = (ContentModelControllerHome) 
     ctx.lookup(ContentModelControllerHome.CONTENT_MODEL_CONTROLLER_JNDI_NAME);
if (home != null) {
     result = home.getContentModelControllerProvider().createContentModelController(aContentModel);
}

To obtain a ContentModelController, pass an existing content model to the createContentModelController method of the ContentModelControllerProvider.
Example 2 - Obtaining a layout model controller for a specific page:

// locate the page for which you want to create a LayoutModelController
final Locator locator = cmController.getLocator();
final ContentPage page = (ContentPage) locator.findByUniqueName("MyPage");
 
// create a LayoutModelController
final LayoutModelController lmController = cmController.getLayoutModelController(page);

Parent

Work with controllers
Committing and persisting modifications
Obtaining a model from the portal

 

+

Search Tips   |   Advanced Search