Obtaining a controller for working with resources

 

+

Search Tips   |   Advanced Search

 

To modify, create, or delete portal resources by using the Controller SPI, you first need to create a controller.

You do this by using a JNDI based lookup for the correct "home" interface, that is, the corresponding read-only interface.

The provider lookup for a controller home is possible from servlet level code and portlets.

The following controllers are available via JNDI:

ContentModelController

To obtain a ContentModelController, perform a lookup for the string

ContentModelControllerHome.CONTENT_MODEL_CONTROLLER_JNDI_NAME

PortletModelController

To obtain a ContentModelController, perform a lookup for the string

PortletModelControllerHome.PORTLET_MODEL_CONTROLLER_JNDI_NAME

The LayoutModelController cannot be obtained via a JNDI lookup. You obtain it through its associated ContentModelController.

 

Example - Obtaining a content model controller:

To obtain a ContentModelController, pass an existing content model to the createContentModelController method of the ContentModelControllerProvider.

ContentModelController result = null;
 final Context ctx = new InitialContext();
 final ContentModelControllerHome home = (ContentModelControllerHome) 
      ctx.lookup(ContentModelControllerHome.CONTENT_MODEL_CONTROLLER_JNDI_NAME);
 if (home != null) 
{
     result = home.getContentModelControllerProvider().createContentModelController(aContentModel);
}

 

Example 2 - Obtaining a layout model controller for a specific page:

// locate the page for which you want to create a LayoutModelController final Locator locator = cmController.getLocator(); final ContentPage page = (ContentPage) locator.findByUniqueName("MyPage");

// create a LayoutModelController final LayoutModelController lmController = cmController.getLayoutModelController(page);